At equilibrium condition, the chemical potential of a material in different phases in contact with each other is equal. The chemical potential for a real gas (μ) is given by (where, μ = standard chemical potential at unit fugacity (f° = 1 atm.) and the gas behaves ideally.) ?

Question

Accepted Answer

μ° + RT ln f. The chemical potential for a real gas is given by $\mu = \mu^\circ + RT \ln(f/P^\circ)$. Since $f^\circ$ is 1 atm, the equation simplifies to $\mu = \mu^\circ + RT \ln f$.