A multiple effect evaporator has a capacity to process 4000 kg of solid caustic soda per day, when it is concentrating from 10% to 25% solids. The water evaporated in kg per day is__________________?

Question

Accepted Answer

24000. The mass of water evaporated is the difference between the initial and final total mass. Initial mass = 4000 kg / (1 - 0.10) * 0.10; Final mass = 4000 kg / (1 - 0.25) * 0.25. Evaporated water = Initial Total Mass - Final Total Mass.