What is the value of ‘n’ if the reaction rate of the chemical reaction A → B, is proportional to CA n and it is found that the reaction rate triples, when the concentration of ‘A’ is increased 9 times ?
Correct answer: A
Explanation
The rate law is Rate = k[A]^n. If the rate triples (3) when [A] increases 9 times (9), then $3 = 9^n$, so $n=1/2$.