A batch adiabatic reactor at an initial temperature of 373°K is being used for the reaction, A → B. Assume the heat of reaction is – 1kJ/mole at 373°K and heat capacity of both A and B to be constant and equal to 50J/mole.K. The temperature rise after a conversion of 0.5 will be ____________?
Correct answer: B
Explanation
The temperature rise is calculated by $\Delta T = \frac{(-\Delta H_r) \cdot X}{C_{p,avg}}$. Plugging in the values gives $10^{\circ}\text{C}$.