The average molecular weight of a flue gas having the composition by volume as CO2 = 25%, O2 = 25%, N2 = 50% will be___________________?
Correct answer: B
Explanation
The average molecular weight is calculated by summing (mole fraction * molecular weight) for each gas. Calculation: (0.25*44 + 0.25*32 + 0.50*28.01) = 27.6.