Colebrook equation for friction factor in turbulent flow is given by, f-0.5 = -4 loge [(ε/D) + (1.26/NRe √F). It reduces to Nikuradse equation for a value of (ϵ/D) equal to __________________?
Correct answer: A
Explanation
The Colebrook equation reduces to the Nikuradse equation when the relative roughness (ε/D) approaches zero.