A 30% (by volume) suspension of spherical sand particles in a viscous oil has a hindered settling velocity of 4.44 μm/s. If the Richardson Zaki hindered settling index is 4.5, then the terminal velocity of a sand grain is_________________?

Question

Accepted Answer

1 μm/s. The terminal velocity (v0) is found by dividing the hindered settling velocity (v) by the Richardson-Zaki index (n): v0 = v / n. So, v0 = 4.44 μm/s / 4.5 ≈ 0.987 μm/s, which is closest to 1 μm/s.