The amount of Zn (atomic weight = 65) required to form 224 c.c. of H2 at N.T.P. on treatment with dilute H2SO4will be _____________ gm?
Correct answer: C
Explanation
At NTP, 224 c.c. of H2 is 0.01 moles. The reaction Zn + H2SO4 -> ZnSO4 + H2 shows a 1:1 mole ratio, so 0.01 moles of Zn are needed. Mass = 0.01 * 65 = 0.65 gm.