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Correct answer: B
Explanation
Reversing a reaction changes the sign of the enthalpy change. If $\Delta H$ for $C + O_2 \rightleftharpoons CO_2$ is $-94 \text{ kcal}$, then for the reverse reaction $CO_2 \rightarrow C + O_2$, $\Delta H$ must be $+94 \text{ kcal}$.